![]() Then you can use the formula given below. This is because the power rating depends not only on the watts but also on the voltage.Īs a result, to know the amperage rating of 3500 watts, you should know how many volts is 3500 watts using first. Therefore, a 60W light bulb used 5 hours a day consumes 300 watt hours or 0.3KWh of electricity.In general, to get the amperage rating in terms of wattage, you need to consider the voltage rating of the circuit. ![]() To determine KWhs, multiply Kilowatts by number of hours of use. Your utility bill, supplied monthly by your electric provider, is reported in Kilowatt Hours (KWh) of use (1 Kilowatt = 1000W). They are very efficient, use little electricity and therefore result in an immediate decrease in your electric bill. They last upward of 50,000 hours meaning if you leave a new LED bulb on for 8 hours/day it would not need to be changed for over 10 years. LED bulbs replace 75W-100W incandescent bulbs with equal light output while consuing a ere 3W-13W. ![]() The rule of thumb in the renewable energy industry is that for every dollar invested replacing inefficient appliances, three dollars is saved in the cost of a renewable energy system to run them. Alternatives such as LP or natural gas for water/space heating or cooking, evaporative cooling instead of compressor based AC units, and passive solar ideas are cost-saving options. Appliances that run at 240V AC- such as electric water heaters, cook-stoves, furnaces and air conditioners, are impractical loads to run on solar- whether generator or grid-tie. You can therefore run more of these types of appliances on a Sunrnr. The efficiency level is lessened if a 12V AC powered refrigerator is connected to a 12V DC electrical circuit using an inverter.Īlso, LED (light-emitting diodes) bulbs and Energystar rated appliances consume less energy and operate more efficiently. For instance a 12V DC electrical circuit that supports a refrigerator will use power more efficiently if the refrigerator also operates at 12V DC. Please note that the proper selection of AC or DC appliances is an important factor, because it is better to have the power source and appliance working at the same voltage, so that, in a manner of speaking, nothing is lost in the conversion. ![]() Therefore, adding up a m ps figures for the various appliances you intend to plug into a Sunrnr will give you the total electrical load you will put on the equipment (or demand that it powers). To determine Amps consumed by a 25watt 12V light bulb, for example, use the equation A=W/V or (25/12=2.1Amps). You can determine power characteristics of an appliance if watts rating is not provided, by the following equation: V (Volts) X A (Amps) = Watts (Ohm's Law) Finally, volts is what energizes the appliance or it is the force that pushes electricity through wire to the appliance. Amps on the other hand is defined as how much energy an appliance draws, or the rate of energy that flows through wire when an appliance is used for 1 hour. Watts is generally defined as the amount of power (or energy) an appliance uses (consumes) when operated at its maximum capacity for 1 hour . Electricity is measured in units of energy called watts, named after James Watt, the inventor of the steam engine.
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